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Question: A certain force gives an object of mass \({m_1}\) an acceleration of \(12.0m/{s^2}\) and an object o...

A certain force gives an object of mass m1{m_1} an acceleration of 12.0m/s212.0m/{s^2} and an object of mass m2{m_2} an acceleration of 3.30m/s23.30m/{s^2}. What acceleration would the force give to an object of mass
(A) m1+m2{m_1} + {m_2}
(B) m2m1{m_2} - {m_1}

Explanation

Solution

There is a particular force that gives an object of mass m1{m_1}an acceleration of 12.0m/s212.0m/{s^2}. The same force gives another object of mass m2{m_2} an acceleration of 3.30m/s23.30m/{s^2}. We have to find the acceleration produced by the same force on an object of mass m1+m2{m_1} + {m_2} and m2m1{m_2} - {m_1}.

Complete step by step solution:
Let us assume that the force is FF.
The force can be written as,
F=maF = ma
where mm stands for the mass of the object and aa stands for the acceleration.
From this, we can write the mass as,
m=Fam = \dfrac{F}{a}
Therefore, the mass m1{m_1} can be written as,
m1=Fa1{m_1} = \dfrac{F}{{{a_1}}}
The mass m2{m_2} can be written as,
m2=Fa2{m_2} = \dfrac{F}{{{a_2}}}
Now, the acceleration on the object of mass m1+m2{m_1} + {m_2} will be,
a=Fm1+m2a = \dfrac{F}{{{m_1} + {m_2}}}
Substituting for m1{m_1} and m2{m_2}
We get
a=F(Fa1)+(Fa2)a = \dfrac{F}{{\left( {\dfrac{F}{{{a_1}}}} \right) + \left( {\dfrac{F}{{{a_2}}}} \right)}}
This can be written as,
a=11a1+1a2=a1a2a1+a2a = \dfrac{1}{{\dfrac{1}{{{a_1}}} + \dfrac{1}{{{a_2}}}}} = \dfrac{{{a_1}{a_2}}}{{{a_1} + {a_2}}}
Given that a1=12.0m/s2{a_1} = 12.0m/{s^2} and m2=3.30m/s2{m_2} = 3.30m/{s^2}
Substituting, we get
a=12×3.3012+3.30=2.59m/s2a = \dfrac{{12 \times 3.30}}{{12 + 3.30}} = 2.59m/{s^2}
Therefore the acceleration produced by the force FF on an object of mass m1+m2=2.59m/s2{m_1} + {m_2} = 2.59m/{s^2}
The acceleration produced by the force FF on an object of mass m2m1{m_2} - {m_1} will be
a=Fm2m1a = \dfrac{F}{{{m_2} - {m_1}}}
Substituting for m1{m_1} and m2{m_2}
We get
a=FFa2Fa1a = \dfrac{F}{{\dfrac{F}{{{a_2}}} - \dfrac{F}{{{a_1}}}}}
This can be written as,
a=11a21a1=a1a2a1a2a = \dfrac{1}{{\dfrac{1}{{{a_2}}} - \dfrac{1}{{{a_1}}}}} = \dfrac{{{a_1}{a_2}}}{{{a_1} - {a_2}}}
Substituting the values of a1{a_1} and a2{a_2} we get,
a=12×3.30123.30=4.55m/s2a = \dfrac{{12 \times 3.30}}{{12 - 3.30}} = 4.55m/{s^2}
The acceleration produced by a force FF on an object of mass m2m1=4.55m/s2{m_2} - {m_1} = 4.55m/{s^2}

Additional information:
Every moving body has a property due to its motion called momentum. It can be defined as the product of the mass of the object and its velocity.

Note: The relation between the force applied on an object and the acceleration produced by that object due to force is given by Newton’s second law of motion. The second law enables us to measure the force. According to the second law of motion, the net force acting on an object is directly proportional to the rate of change of momentum.