Question

A certain engine which operates in a carnot cycle absorbs 3.347 kJ at 400ŗC, how much work is done by the engine per cycle ? The temperature of sink is 100ŗC.

• A. 1.49 kJ
• B. 2.51 kJ
• C. 1.85 kJ
• D. 2.98 kJ

Answer 1

Answer: (A)

1.49 kJ

Answer 2

h =$\frac{T_{2} - T_{1}}{T_{2}}$ = 1– $\frac{T_{1}}{T_{2}}$ = 1–$\frac{373}{673}$ = 0.446

h = $\frac{\Delta w}{q_{1}}$

or DW = h × q₁ = 0.446 × 3.347 = 1.49 kJ