Solveeit Logo
Login

Question

Question: A certain compound X imparts a golden yellow flame. When zinc powder is heated with a concentrated s...

A certain compound X imparts a golden yellow flame. When zinc powder is heated with a concentrated solution of X, H2{H_2} gas is evolved. X combines with CO2C{O_2} to have a saltY. Y is a hydrated salt which in reaction with HClHCl or an excess of CO2C{O_2} gives another salt Z which is an important part of baking powder. Identify X, Y and Z.
A.X−NaOH,Y−Na2CO3,Z−NaHCO3X - NaOH,Y - N{a_2}C{O_3},Z - NaHC{O_3}
B.X−HCl,Y−NaOH,Z−NaHCO3X - HCl,Y - NaOH,Z - NaHC{O_3}
C.X−KOH,Y−K2CO3,Z−KHCO3X - KOH,Y - {K_2}C{O_3},Z - KHC{O_3}
D.X−NaCl,Y−Na2CO3,Z−NaOHX - NaCl,Y - N{a_2}C{O_3},Z - NaOH

Explanation

Solution

The flame colour is also used to test the compounds although it is the preliminary step towards detecting the presence of the particular compound in the sample under examination and a chemical confirmatory test is essentially needed.

Complete step by step answer:
The burner named after the scientist Robert Bunsen is known as Bunsen burner and is a burner commonly used in the laboratory it is a gas burner. It produces a single flame and the flame is also open and the process of sterilization, heating and combustion is usually carried out with this.
Yellow colour is imparted by Sodium hydroxide when it is heated over the Bunsen burner. When the concentrated solution of sodium hydroxide is heated with zinc powder hydrogen gas is evolved in the reaction. The compound sodium hydroxide combines with carbon dioxide and gives sodium carbonate. The hydrated salt sodium carbonate on the reaction with HCl or in the presence of the excess of the carbon dioxide gives Sodium bicarbonate salt. The sequence of the steps or the reactions are shown below:
Zn+2NaOH(X)→Na2ZnO2+H2 2NaOH+CO2→Na2CO3(Y)+H2O Na2CO3(Y)+HCl→NaHCO3(Z)+NaCl Na2CO3+CO2+H2O→2NaHCO3   Zn + 2NaOH(X) \to N{a_2}Zn{O_2} + {H_2} \\\ 2NaOH + C{O_2} \to N{a_2}C{O_3}(Y) + {H_2}O \\\ N{a_2}C{O_3}(Y) + HCl \to NaHC{O_3}(Z) + NaCl \\\ N{a_2}C{O_3} + C{O_2} + {H_2}O \to 2NaHC{O_3} \\\ \\\
Thus the compounds X, Y and Z will be: X−NaOH,Y−Na2CO3,Z−NaHCO3X - NaOH,Y - N{a_2}C{O_3},Z - NaHC{O_3} and the option A will be the correct answer.

Note:
Sodium compounds and their derivatives are frequently used in the baking industry in order to prepare the different compounds and they are very versatile compounds since the lot of compounds from them can be prepared based on the requirement simply by altering the reaction conditions and the physical parameters.