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Question: A certain charge liberates 0.8 gm of \(O_{2}\). The same charge will liberate how many gm of silver...

A certain charge liberates 0.8 gm of O2O_{2}. The same charge will liberate how many gm of silver

A

108 gm

B

10.8 gm

C

0.8 gm

D

1080.8gm\frac{108}{0.8}gm

Answer

10.8 gm

Explanation

Solution

Mass of O2 ionsMass of Ag ions=Chemical equivalent of O2Chemical equivalent of Ag\frac{\text{Mass of }O_{2}\text{ ions}}{\text{Mass of }Ag\text{ ions}} = \frac{\text{Chemical equivalent of }O_{2}}{\text{Chemical equivalent of }Ag}

0.8m=8108\frac{0.8}{m} = \frac{8}{108}m=10.8gmm = 10.8gm