Question

A certain amount of gas of volume V at 27°C temperature and pressure 2 × 107 Nm–2 expands isothermally until its volume gets doubled. Later it expands adiabatically until its volume gets redoubled. The final pressure of the gas will be (Use, γ = 1.5)

• A. $3.536\times10^5$Pa
• B. $3.536\times10^6$ Pa
• C. $1.25\times10^6$ Pa
• D. $1.25\times10^5$Pa

Answer 1

Answer: (B)

$3.536\times10^6$ Pa

Answer 2

P1=2×107 Pa
P1V1=P2V2
Since V2=2V1 Hence P2=$\frac{P_1}{2}$ (isothermal expansion)
P2=1×107Pa
P2V2γ=P2V2γ
P3=$\frac{1×10^7}{2^1.5}$=3.536×106