Question

A cell whose e.m.f. is 2 V and internal resistance is $0.1 \Omega$, is connected with a resistance of$3.9 \Omega$. The voltage across the cell terminal will be

• A. 0.50 V
• B. 1.90 V
• C.
• D. 2.00 V

Answer 1

Answer: (C)

Answer 2

The voltage across cell terminal will be given by

$= \frac { E } { R + r } \times R$ $= \frac { 2 } { ( 3.9 + 0.1 ) } \times 3.9 = 1.95 \mathrm {~V}$