Question
Physics Question on Current electricity
A cell of internal resistance r drives current through an external resistance R. The power delivered by the cell to the external resistance will be maximum when
A
R = 1000 r
B
R = 0.001 r
C
R = 2r
D
R = r
Answer
R = r
Explanation
Solution
Current i=r+RE
Power generated in R
P=i2R
P=(r+R)2E2R
for maximum power dRdP=0
E2[(r+R)4(r+R)2×1−R×2(r+R)]=0
⇒r=R