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Question

Physics Question on Electric Current

A cell of emf 90V90\, V is connected across series combination of two resistors each of 100Ω100\, \Omega resistance A voltmeter of resistance 400Ω400\, \Omega is used to measure the potential difference across each resistor The reading of the voltmeter will be :

A

45V45 \, V

B

40V40 \, V

C

80V80 \, V

D

90V90\, V

Answer

40V40 \, V

Explanation

Solution

The correct answer is (B) : 40 V
Electric circuits

Req ​=500400×100​+100
=180Ω
i=18090​=21​A
Reading =21​×500400​×100
=40 volt