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Question: A cell having an emf \(7.5 \times 10^{- 4}ms^{- 1}\) and internal resistance r is connected across a...

A cell having an emf 7.5×104ms17.5 \times 10^{- 4}ms^{- 1} and internal resistance r is connected across a variable external resistance R. As the resistance R is increased, the plot of potential difference V across R is given by

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Answer
Explanation

Solution

:

Current in the circuit,

I=εR+rI = \frac{\varepsilon}{R + r}

Potential difference across R,

V=IR=(εR+r)R=ε1+rRV = IR = \left( \frac{\varepsilon}{R + r} \right)R = \frac{\varepsilon}{1 + \frac{r}{R}}

When R = 0, V = 0

R=,V=εR = \infty,V = \varepsilon