Solveeit Logo

Question

Physics Question on Resistance

A cell has terminal voltage 2V2\, V in open circuit and internal resistance of the given cell is 2O2O. If 4A4\, A of current is flowing between points PP and QQ in the circuit and then the potential difference between PP and QQ is

A

30V30\, V

B

26V26\, V

C

22V22\, V

D

24V24\, V

Answer

26V26\, V

Explanation

Solution

Key Point Find the terminal potential difference in case of charging a battery.

According to question, it is the case of charging of battery. So, terminal potential difference is given by
TPD=VPVR=E+Ir=2+(4×2)TPD =V_{P}-V_{R}= E+I_{r}=2+(4 \times 2)
=10V=10\, V ...(i)
Again, VRVQ=4×4=16VV_{R}-V_{Q}=4 \times 4=16\, V ...(ii)
From Eqs. (i) and (ii), we get
VPVR+VRVQ=10+16V_{P}-V_{R}+V_{R}-V_{Q}=10+16
VPVQ=26V\Rightarrow V_{P}-V_{Q}=26\, V