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Physics Question on Semiconductor electronics: materials, devices and simple circuits

A CECE amplifier has current gain 50. Load resistance is 4 kΩ4 \, k\Omega and input resistance is 500 Ω.10 mV AC500 \, \Omega . 10 \, m V \, AC signal is applied. Peak value of output signal is

A

2 V

B

4 V

C

40 V

D

20 V

Answer

4 V

Explanation

Solution

Here, Ri=500 Ω,RL=4 kΩ=4000 Ω R_i = 500 \, \Omega , R_L = 4 \, k \Omega = 4000 \, \Omega
Current gain,β=50,Vi=10 mV=10−2 V\beta = 50, V_i = 10 \, mV = 10^{-2} \, V
Voltage gain, A=βRLRiA = \beta \frac{R_L}{R_i} or, VoVi=βRLRi \frac{V_o}{V_i} = \beta \frac{R_L}{R_i}
∴ Vo=50×4000500×10−2=4V\therefore \, V_o = 50 \times \frac{4000}{500} \times 10^{-2} = 4 V