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Question: A cart loaded with sand moves along a horizontal plane due to a constant force F in the direction of...

A cart loaded with sand moves along a horizontal plane due to a constant force F in the direction of velocity. Through a small hole in the bottom sand spills out at m kgs-1. Find the velocity of the cart at any time t. Initial mass of the cart is m0.

A

Fmlogem0m0mt\frac { F } { m } \log _ { e } \frac { m _ { 0 } } { m _ { 0 } - m t }

B

Fm0logem0m0mt\frac { F } { m _ { 0 } } \log _ { e } \frac { m _ { 0 } } { m _ { 0 } - m t }

C

Fm0\frac { \mathrm { F } } { \mathrm { m } _ { 0 } } t

D

Fm\frac { \mathrm { F } } { \mathrm { m } } t

Answer

Fmlogem0m0mt\frac { F } { m } \log _ { e } \frac { m _ { 0 } } { m _ { 0 } - m t }

Explanation

Solution

Mass of the cart at any instant is m0 – mt

acceleration a = dvdt=Fm0mt\frac { d v } { d t } = \frac { F } { m _ { 0 } - m t }

v = 0tFm0mtdt=Fmlogem0m0mt\int _ { 0 } ^ { t } \frac { F } { m _ { 0 } - m t } d t = \frac { F } { m } \log _ { e } \frac { m _ { 0 } } { m _ { 0 } - m t } .