Question
Question: A carpet of mass \(M\), made of an extensible material is rolled along its length in the form of a c...
A carpet of mass M, made of an extensible material is rolled along its length in the form of a cylinder of radius R and kept on a rough floor. If the carpet is unrolled, without sliding to a radius 2R, the decrease in potential energy is
& A.\dfrac{1}{2}MgR \\\ & B.\dfrac{7}{8}MgR \\\ & C.\dfrac{5}{8}MgR \\\ & D.\dfrac{3}{4}MgR \\\ \end{aligned}$$Solution
We know that potential energy is energy possessed by an object due to its position. To find the change in the potential energy, we need to calculate the individual energies of the cylindrical carpet and the carpet on the floor. Then calculating the difference between the both gives the change in the potential energy.
Formula used:
P.E=mgh, where P.E is the potential energy of a body with mass m which is at a height h from the ground and g is acceleration due to gravity.
Complete step-by-step answer:
Given that the cylinder of carpet of mass M and radius R is rolled on the floor to give a radius 2R.
Let us assume that the density of the carpet is given as ρ then, since the same cylinder is rolled to a radius2R, the density of the carpet on the floor is also ρ .
Then, equating the densities, we get πR2M=π(2R)2m
Then, we see that m=4M
Now potential energy is given as P.E=mgh, here the radius of the carpet will give the height of the carpet.
Then, the potential energy when the carpet is kept as a cylinder is given as P.E1=MgR
Similarly, the potential energy when the carpet when unrolled on the floor is given as P.E2=mg2R=g⋅4M⋅2R=8MgR
Then the difference in potential energy is given as ΔP.E=P.E2−P.E1
Substituting, we get ΔP.E=8MgR−MgR=87MgR
Hence the answer is option B.87MgR
So, the correct answer is “Option B”.
Note: The initial potential energy is straight forward. Clearly, here the radius or the height of the carpet varies when it is rolled on the floor. But the density of the carpet is a constant. Since density depends on mass, then we can find the new mass and then the new potential energy.