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Question: A Carnot’s cycle operating between T1 = 600 K and T2 = 300 K producing 1.5 kJ of mechanical work per...

A Carnot’s cycle operating between T1 = 600 K and T2 = 300 K producing 1.5 kJ of mechanical work per cycle. The heat transferred to the engine by the reservoirs

A

2.5 kJ

B

3 kJ

C

3.5 kJ

D

4 kJ

Answer

3 kJ

Explanation

Solution

Here T1=600k,T2=300k,W=1.5kJ=1500JT_{1} = 600k,T_{2} = 300k,W = 1.5kJ = 1500J

As η=1T2T1=1300600=12\eta = 1 - \frac{T_{2}}{T_{1}} = 1 - \frac{300}{600} = \frac{1}{2}

Also, η=workdoneheatsupplied=WQ1\eta = \frac{workdone}{heat\sup plied} = \frac{W}{Q_{1}}

Q1Wη=15001/2=3000J=3kJ\therefore Q_{1}\frac{W}{\eta} = \frac{1500}{1/2} = 3000J = 3kJ