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Question

Physics Question on Thermodynamics

A Carnot's engine is made to work between 200C200^\circ \,C and 0C0^\circ \,C first and then between 0C0^\circ \,C and 200C-200^\circ \,C. The ratio of efficiencies of the engine is the two cases is

A

1.73 : 1

B

01:01.7

C

1:01

D

1:02

Answer

01:01.7

Explanation

Solution

η=1T2T1\eta=1-\frac{T_2}{T_1}
η1=1273473=200473\therefore\,\eta_1=1-\frac{273}{473}=\frac{200}{473}
η1=173273=200273\eta_1=1-\frac{73}{273}=\frac{200}{273}
η1/η2=273473=11.73\therefore\,\eta_1/\eta_2=\frac{273}{473}=\frac{1}{1.73}