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Question

Physics Question on carnot cycle

A Carnot engine working between 300 K and 600 K has a work output of 800 joules per cycle. The amount of heat energy supplied from the source to the engine in each cycle is

A

6400 joule

B

1600 joule

C

3200 joule

D

800 joule

Answer

1600 joule

Explanation

Solution

: Efficiency =outputinput=1T2T1=\frac{output}{input}=1-\frac{{{T}_{2}}}{{{T}_{1}}} Or 800input=1300600800input=12\frac{800}{input}=1-\frac{300}{600}\Rightarrow \frac{800}{input}=\frac{1}{2} Or input=1600Jinput=1600J