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Question

Physics Question on Thermodynamics

A Carnot engine working between 300K300\, K and 400K400\, K has 800J800\, J of useful work. The amount of heat energy supplied to the engine from the source is

A

2400 J

B

3200 J

C

1200 J

D

3600 J

Answer

3200 J

Explanation

Solution

η= Work done  Heat supplied \eta =\frac{\text { Work done }}{\text { Heat supplied }}
=T1T2T1=WQ1=\frac{T_{1}-T_{2}}{T_{1}}=\frac{W}{Q_{1}}
W=800J,T1=400K,T2=300KW =800\, J , T_{1}=400\, K , T_{2}=300 \,K
On substitution the values
800Q1=400300400\frac{800}{Q_{1}} =\frac{400-300}{400}
=100400=14=\frac{100}{400}=\frac{1}{4}
Q1=800×4=3200JQ_{1} =800 \times 4=3200\, J