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Question

Physics Question on Work-energy theorem

A Carnot engine takes 5000 kcal of heat from a reservoir at 727°C and gives heat to a sink at 127°C. The work done by the engine is

A

3×1063 × 10^6 J

B

Zero

C

12.6×10612.6 × 10^6 J

D

8.4×1068.4 × 10^6 J

Answer

12.6×10612.6 × 10^6 J

Explanation

Solution

EfficiencyEfficiency

η=1TLTHη = 1 - \frac{T_L}{T_H}

= 140010001 - \frac{400}{1000}

= 0.60.6

0.6=WQ0.6 = \frac{W}{Q}

W=0.6Q=3000  KcalW = 0.6 Q = 3000\; Kcal

= 12.6×106  J12.6 \times 10^6 \;J