Question

A Carnot engine operating between two reservoirs has efficiency $\frac{1}{3}$ When the temperature of cold reservoir raised by $x$, its efficiency decreases to $\frac{1}{6}$ The value of $x$, if the temperature of hot reservoir is $99^{\circ} C$, will be :

• A. $62 K$
• B. $16.5 I$
• C. $33 K$
• D. $66 K$

Answer 1

Answer: (A)

$62 K$

Answer 2

The correct answer is (A) : 62 K
TH​=99∘C=99+273
=372K
1−TH​TC​​=31​
TH​TC​​=32​(1)⇒TC​=32​×372
=2×124=248K
1−TH​TC​+X​=61​
65​=TH​TC​+X​
65​=372248+X​
248+X=5×62
X=310−248=62K