Question

A carnot engine absorbs 750 K of heat energy from a reservoir at 137°C and rejects 500 J of heat during each cycle, then the temperature of sink is

• A. 0.25°C
• B. 0.34°C
• C. 0.44°C
• D. 0.54°C

Answer 1

Answer: (B)

0.34°C

Answer 2

Here,

$T_{1} = 273 + 173 = 410,Q_{1} = 750J,Q_{2} = 500J$

As, $\frac{Q_{2}}{Q_{1}} = \frac{T_{2}}{T_{1}}$

$\Rightarrow T_{2} = \frac{Q_{2}}{Q_{1}}T_{1} = \frac{500}{750} \times 410$

$= 273.34k = 273.34 - 273 = 0.34ºC$