A Carnot engine absorbs (6\times10^5) cal at 227°C. The work... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A Carnot engine absorbs $6\times10^5$ cal at 227°C. The work done per cycle by the engine, if its sink is maintained at 127°C is

A

$15 \times 10^8\ J$

B

$15 \times 10^4\ J$

C

$5 \times 10^5\ J$

D

$2 \times 10^4\ J$

Answer

$5 \times 10^5\ J$

Explanation

Solution

The correct option is (C): $5 \times 10^5\ J$ .