Solveeit Logo

Question

Physics Question on Current electricity

A carbon resistor of (47±4.7)kΩ(47 \pm 4.7) \, k \Omega is to be marked with rings of different colours for its identification. The colour code sequence will be

A

Green - Orange- Violet- Gold

B

Violet - Yellow - Orange - Silver

C

Yellow - Green - Violet - Gold

D

Yellow - Violet - Orange - Silver

Answer

Yellow - Violet - Orange - Silver

Explanation

Solution

(47±4.7)kΩ=47×103±10%(47 \pm 4.7)\, k \Omega = 47 \times 10^3 \pm 10 \%
\therefore Yellow - Violet - Orange - Silver