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Question

Physics Question on Current electricity

A carbon film resistor has colour code Green Black Violet Gold. The value of the resistor is

A

50MΩ50\, M \Omega

B

500MΩ500\, M\Omega

C

500±5%MΩ500 \pm 5 \% M \Omega

D

500±10%MΩ500 \pm 10 \% M \Omega

Answer

500±5%MΩ500 \pm 5 \% M \Omega

Explanation

Solution

Corresponding to the colours of the first and second bands green and black, the figures are 5 and 0 .
Corresponding to the colour of third band, violet, the multiplier is 10710^{7}. Therefore, the value of the resistance is 50×107Ω50 \times 10^{7} \Omega. The Gold colour of the fourth band, indicates the tolerance of 5%5 \%
So, the value of the resistor is written as
50×107Ω±5%=500×106Ω+5%50 \times 10^{7} \Omega \pm 5 \% =500 \times 10^{6} \Omega+5 \%
=500±5%MΩ=500 \pm 5 \% M \Omega