A car travels a distance of ' (x) ' with speed (v\_1) and th... | Physics | SolveeIt | Solveeit

Today, August 18

Question

A car travels a distance of ' $x$ ' with speed $v_1$ and then same distance ' $x$ ' with speed $v_2$ in the same direction The average speed of the car is:

A

$\frac{v_1 v_2}{2\left(v_1+v_2\right)}$

B

$\frac{2 x}{v_1+v_2}$

C

$\frac{2 v_1 v_2}{v_1+v_2}$

D

$\frac{v_1+v_2}{2}$

Answer

$\frac{2 v_1 v_2}{v_1+v_2}$

Explanation

Solution

A car travels a distance of x with speed v1 and then same distance x with speed v2

Average velocity = Total time Total displacement
=v1x+v2xx+x=v1+v22v1v2