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Question: A car starts from rest, moves with an acceleration a and then decelerates at b for sometime to come ...

A car starts from rest, moves with an acceleration a and then decelerates at b for sometime to come to rest. If the total time taken is t, the maximum velocity is

A

abt/a + b

B

a2t/a + b

C

at/a + b

D

b2t/a + b

Answer

abt/a + b

Explanation

Solution

v = 0 + at1; 0 = at1- b(t – t1)

or t1 = bt/a + b

∓ vmax = abt/a + b