Question

A car of mass 200 kg is revolving in a circular track of radius 70 m with angular velocity of 0.2 rad/sec, then find the centripetal force in newton.

Answer 1

The centripetal force (F) required to keep an object of mass m moving in a circular path of radius r with angular velocity ω is given by:
$F = mω^2r$
In this case, the mass of the car is 200 kg, the radius of the circular track is 70 m, and the angular velocity of the car is 0.2 rad/s.
Substituting these values into the above formula, we get:
F = $(200 kg) * (0.2 rad/s)^2 * (70 m) = 560 N$
Therefore, the centripetal force required to keep the car moving in a circular track of radius 70 m with angular velocity of 0.2 rad/sec is 560 N.
So, Answer is 560.