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Question

Physics Question on Motion in a straight line

A car moves a distance of 200 m. It covers the first half of the distance at speed 40 km/h and the second half of distance at speed v. The average speed is 48 km/h. The value of v is

A

56 km/h

B

60 km/h

C

50 km/h

D

48 km/h

Answer

60 km/h

Explanation

Solution

Total distance travelled = 200 m
Total time taken =10040+100v=\frac{100}{40}+\frac{100}{v}
Average speed =totaldistancetravelledtotaltimetaken=\frac{total\, distance\, travelled}{total\, time\, taken}
48=200(10040+100v)48=\frac{200}{\bigg(\frac{100}{40}+\frac{100}{v}\bigg)} or 48=2(140+1v)48=\frac{2}{\bigg(\frac{1}{40}+\frac{1}{v}\bigg)}
or 140+1v=124\, \, \frac{1}{40}+\frac{1}{v}=\frac{1}{24}
or 1v=124140=53120=160\, \, \frac{1}{v}=\frac{1}{24}-\frac{1}{40}=\frac{5-3}{120}=\frac{1}{60}
or v=60km/hr \, \, v = 60\, km/hr