Question

A car is travelling at a velocity of 10 kmh^-1 on a straight road. The driver of car throws a parcel with a velocity of 10√2 kmh^-1 when car is passing by a man standing on the side of a road. If parcel just reaches the man, the direction of throw makes following angle with the direction of car

• A. 135⁰
• B. 45⁰
• C. tan^-1 (√2)
• D. tan (1/√2)

Answer 1

Answer: (A)

135⁰

Answer 2

When the car is exactly opposite, the man at least distance, the bag will reach him when thrown with velocity v₀.

sin θ = $\frac{v_{b}}{v_{c}} = \frac{10}{10\sqrt{2}} = \frac{1}{\sqrt{2}}$

or θ = 45⁰

∴ total angle between v_c and v_b is 90 + 45 = 135⁰