Question

A car is standing $200\, m$ behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration $2 \, m/s^2$ and the car has acceleration $4 \, m/s^2$. The car will catch up with the bus after a time of :

• A. $\sqrt{110} s$
• B. $\sqrt{120} s$
• C. $10 \sqrt{2} s$
• D. $15\, s$

Answer 1

Answer: (C)

$10 \sqrt{2} s$

Answer 2

$a_{CB} = 2 \,m/sec ^2$
$200=\frac{1}{2}\times2t^{2}$
$t=10\sqrt{2}$ second