Question
Physics Question on laws of motion
A car is moving with speed 20m s−1 on a circular path of radius 100m . Its speed is increasing at a rate of 3m s−2 . The magnitude of the acceleration of the car at that moment is
A
1m s−2
B
3m s−2
C
4m s−2
D
5m s−2
Answer
5m s−2
Explanation
Solution
Given v=20m s−1, R=100m dtdv=3m s−2 ac=Rv2=100(20)2=4(m s)−2 at=dtdv=3m s−2 a=ac2+at2=42+32=5m s−2