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Question: A car is moving with speed 20 m/s. Suddenly the driver sees the sign of danger at a distance of 50m;...

A car is moving with speed 20 m/s. Suddenly the driver sees the sign of danger at a distance of 50m; after a certain reaction time t0t_0 he applies brakes to cause deceleration5ms25m{s^{ - 2}}. What is the maximum allowable reaction time t0t_0 to avoid accidents and distance travelled by the during reaction time?

Explanation

Solution

The given problem is from rectilinear motion. To avoid an accident of a car first we calculate the minimum distance covered with deceleration of 5ms25m{s^{ - 2}}. After that we calculate maximum allowable reaction time to cover 50m distance.

Complete step by step answer:
The given data regarding motion is
Speed (u)= 20m/s
Distance to avoid accident (d)= 50m
Retardation(a)= 5ms25m{s^{ - 2}}
To avoid an accident of a car first we calculate the minimum distance covered with deceleration of 5ms25m{s^{ - 2}}. After that we calculate maximum allowable reaction time to cover 50m distance.

Let the possible reaction time is t0{t_0} , So the car moves 20t020{t_0} meter due to uniform motion in the reaction time.
After that he applies brakes with retardation of 5m/s2. The distance covered with this retardation is given by the equation of motion for uniform acceleration motion.
v2=u2+2as{v^2} = {u^2} + 2as
Due to retardation the sign of acceleration will be negative in this equation.
Here v= Final speed= Zero (to avoid accident)
u= initial speed
s= travelled distance
After putting all the values in this equation, we will get the value of travelled distance to stop the car with retardation of 5m/s2.
0=202+2(5)0 = {20^2} + 2( - 5)
From this, the value of s will be
s=40010=40ms = \dfrac{{400}}{{10}} = 40m

So the total distance covered by car in t0t_0 time and retardation time is (20t0t_0+40) meter. This travelled distance should be less than 50m to avoid an accident with a car.
So, the value of reaction time will be
20t0+4050 20t05040 20t010 t00.5sec  20{t_0} + 40 \leqslant 50 \\\ \Rightarrow 20{t_0} \leqslant 50 - 40 \\\ \Rightarrow 20{t_0} \leqslant 10 \\\ \therefore {t_0} \leqslant 0.5\sec \\\
The value of reaction time will be less than 0.5 seconds to avoid an accident with the car.

Note: Sometimes the retardation of the car or deceleration of the car is taken positively in the equation of motion. We should always remember that the acceleration is a vector quantity, so the direction of it should be considered in the equation to get the right result.