Question

A car is moving on an unbanked circular bend of radius 50 m at a speed of 36 km/hr. The angle of banking required for the safe turning of the car is –

(Take g = 10 m/s²)

• A. tan^–1 (0.5)
• B. tan^–1 (0.2)
• C. tan^–1 ($\sqrt{0.2}$)
• D. tan^–1 ($\sqrt{0.5}$)

Answer 1

Answer: (B)

tan^–1 (0.2)

Answer 2

tan q = $\frac{v^{2}}{rg}$

̃ tan q = $\frac{(10)^{2}}{(500)}$ $\left\lbrack \because\mspace{6mu}\mspace{6mu} 36\frac{km}{hr} = 10\frac{m}{s} \right\rbrack$

= $\frac{100}{500}$

̃ q = tan^–1 (0.2)