Solveeit Logo
Login

Question

Physics Question on laws of motion

A car is moving on a circular level road of curvature 300 m. If the coefficient of friction is 0.30.3 and acceleration due to gravity is 10 m s−210\,m\, s^{-2}, the maximum speed of the car can be

A

90 km h−190\, km\, h^{-1}

B

81 km h−181\, km\, h^{-1}

C

108 km h−1108\, km\, h^{-1}

D

162 km h−1162\, km\, h^{-1}

Answer

108 km h−1108\, km\, h^{-1}

Explanation

Solution

Here, R=300 m,m=0.3,g=10 m s−2R = 300 \,m, m = 0.3, g = 10 \,m \,s^{-2} The maximum speed of the car is υmax=μ Rg=0.3×300 m×10 m s−2\upsilon_{max}=\sqrt{\mu\,Rg}=\sqrt{0.3\times300\,m\times10\,m\,s^{-2}} =30 m s−1=30×185km h−1=108 km h−1=30\,m\,s^{-1}=30\times\frac{18}{5}km\,h^{-1}=108\,km\,h^{-1}