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Question

Physics Question on Current electricity

A car battery of e.m.f. 12V12 V and internal resistance 5×102Ω5 \times 10^{-2} \Omega receives a current of 60A60 A from an external source, then terminal potential difference of battery is :-

A

5V

B

3V

C

15V

D

9V

Answer

15V

Explanation

Solution

Since the battery is drawing 60 A current instead of supplying, it indicates that the battery is being charged then V = E + Ir = 12 + (60 ×\times 5 ×102\times \, 10^{-2}) = 12 + 3 = 15V