Question

A capillary tube of radius $r$ is immersed in water and water rises in it to a height $h$. The mass of water in the capillary tube is $5\,g$. Another capillary tube of radius $2\,r$ is immersed in water. The mass of water that will rise in this tube is

• A. 2.5 g
• B. 5.0 g
• C. 10 g
• D. 20 g

Answer 1

Answer: (C)

10 g

Answer 2

$h=\frac{2S\, cos\, \theta}{r\rho g}$ Mass of water in the first tube, $m=\pi r^{2}h\rho=\pi r^{2}\times\left(\frac{2S \,cos\, \theta}{r\rho g}\right)\times\rho$ $=\frac{2\pi rS\, cos \,\theta}{g}$ $\therefore\, m \propto r.$ Hence, $\frac{m'}{m}=\frac{2r}{r}=2$ or $\, m'=2m=2\times 5 \,g=10\,g.$