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Question: A capillary tube of inner diameter 0.5mm is dipped in a liquid of specific gravity 13.6 and surface ...

A capillary tube of inner diameter 0.5mm is dipped in a liquid of specific gravity 13.6 and surface tension 545dynecm545\dfrac{{dyne}}{{cm}}(angle of contact130130^\circ ). Find the depression or elevation in the tube:
A) Depressed 2.11 cm.
B) Elevated 2.11 cm.
C) Depressed 3.71 cm.
D) Elevated 3.71 cm.

Explanation

Solution

A capillary tube is the tube which has very small diameter and has very long length. The capillary tube will have capillary action and the liquid will rise to the top of the capillary of the tube and there can be seen a depression or elevation on the liquid.

Formula used: The formula of the depression in the capillary tube is given by,
h=4σcosθρgd\Rightarrow h = \dfrac{{4\sigma \cos \theta }}{{\rho gd}}
Where the height is h, the surface tension isσ\sigma , the density isρ\rho , the angle of contact isθ\theta and the diameter of the tube isdd.

Complete step by step solution:
It is given in the problem that a capillary tube of inner diameter 0.5mm is dipped in a liquid of specific gravity 13.6 and surface tension 545dynecm545\dfrac{{dyne}}{{cm}}(angle of contact130130^\circ ) and we need to find the depression or elevation in the tube.
The formula of the depression in the capillary tube is given by,
h=4σcosθρgd\Rightarrow h = \dfrac{{4\sigma \cos \theta }}{{\rho gd}}
Where the height is h, the surface tension isσ\sigma , the density isρ\rho , the angle of contact isθ\theta and the diameter of the tube isdd.
The surface tension is545dynecm545\dfrac{{dyne}}{{cm}}, the angle of contact is130130^\circ , the density is 00136kgcm30 \cdot 0136\dfrac{{kg}}{{c{m^3}}}.
h=2σcosθρgr\Rightarrow h = \dfrac{{2\sigma \cos \theta }}{{\rho gr}}
h=2×545×103×cos13000136×98065×0025\Rightarrow h = \dfrac{{2 \times 545 \times {{10}^{ - 3}} \times \cos {{130}^\circ }}}{{0 \cdot 0136 \times 980 \cdot 65 \times 0 \cdot 025}}
h=2101cm\Rightarrow h = - 2 \cdot 101cm
The depression in the capillary tube is equal to, h211cmh \approx 2 \cdot 11cm.

The correct option for this problem is option A.
As the angle of contact is more than right angle and therefore there will be depression in the tube due to the more cohesive force than the adhesive force.

Note: The capillary tube can have liquid which will form upper meniscus if the angle of contact is greater than right angle and lower meniscus which in case the angle of contact is less than the right angle. In the lower meniscus there is wetting of the glass but in the upper meniscus there is less wetting on the tube surface.