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Question

Physics Question on Units and measurement

A capillary tube is attached horizontally to a constant heat arrangement. If the radius of the capillary tube is increased by 10%, then the rate of flow of liquid will change nearly by

A

0.1

B

0.46

C

-0.1

D

-0.4

Answer

0.46

Explanation

Solution

Volume of liquid coming out of the tube per second V=ppπr48ηl\Rightarrow V = \frac{ p p \pi r^4 }{ 8 \eta l } V2V1=[r2r1]4\Rightarrow \frac{ V_2 }{ V_1 } = \bigg [ \frac{ r_2 }{ r_1 } \bigg ]^4 V2=V1[110100]4\Rightarrow V_2 = V_1 \bigg [\frac{ 110 }{ 100 } \bigg ]^4 = V1(1.1)4=1.4641 V_1 ( 1.1)^4 = 1.4641volt VV\Rightarrow \frac{ \triangle V }{ V } =V2V1V= \frac{ V_2 - V_1 }{ V } =1.4641VV= \frac{ 1.464 1 - V }{ V } =46%= 46\%