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Question: A capacitor with air as the dielectric is charged to a potential of \(100\mspace{6mu} volts\). If th...

A capacitor with air as the dielectric is charged to a potential of 1006muvolts100\mspace{6mu} volts. If the space between the plates is now filled with a dielectric of dielectric constant 10, the potential difference between the plates will be

A

1000 voltsvolts

B

100 voltsvolts

C

10 voltsvolts

D

Zero

Answer

10 voltsvolts

Explanation

Solution

New potential difference

=VK=10010=10V= \frac{V}{K} = \frac{100}{10} = 10V