Question

A capacitor of capacitance $C_{1}$is charged to a potential V and then connected in parallel to an uncharged capacitor of capacitance $C_{2}$The final potential difference across each capacitor will be.

• A. $\frac{C_{1}V}{C_{1} + C_{2}}$
• B. $\frac{C_{2}V}{C_{1} + C_{2}}$
• C. $1 + \frac{C_{2}}{C_{1}}$
• D. $1 - \frac{C_{2}}{C_{1}}$

Answer 1

Answer: (A)

$\frac{C_{1}V}{C_{1} + C_{2}}$

Answer 2

:When a charge capacitor of capacitance $C_{1}$is connected in parallel to an uncharged capacitor of capacitance $C_{2,}$the charge is shared between them till both attain the common potential which is given by,

common potential $= \frac{q_{1} + q_{2}}{C_{1} + C_{2}} = \frac{C_{1}V + 0}{C_{1} + C_{2}} = \frac{C_{1}V}{C_{1} + C_{2}}$