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Question

Physics Question on Electric Flux

A capacitor of capacitance C is charged to a potential V. The flux of the electric field through a closed surface enclosing the positive plate of the capacitor is :

A

CV2ϵ0\frac{CV}{2\epsilon_0}

B

2CVϵ0\frac{2CV}{\epsilon_0}

C

Zero

D

CVϵ0\frac{CV}{\epsilon_0}

Answer

CV2ϵ0\frac{CV}{2\epsilon_0}

Explanation

Solution

The Correct Option is (A):CV2ϵ0\frac{CV}{2\epsilon_0}