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Question: A capacitor of capacitance C is charged to a constant potential difference V and then connected in s...

A capacitor of capacitance C is charged to a constant potential difference V and then connected in series with an open key and a pure resistor R. At time t = 0, the key is closed. If I is current at time t = 0, a plot of log I against t is shown as in the graph (1). Later one of the parameters, i.e. V, R and C is changed, keeping the other two constant and graph (2) is recorded. Then –

A

C is reduced

B

C is increased

C

R is reduced

D

R is increased

Answer

C is increased

Explanation

Solution

It is discharging of capacitor

I = ERet/RC\frac { E } { R } e ^ { - t / R C }

log I = logtRC\frac { \mathrm { t } } { \mathrm { RC } }

Intercept is constant Ž E & R constant

Slope decrease Ž C ↑