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Question: A capacitor of capacitance $C$ and an inductor of inductance $L$ are connected to a DC battery as sh...

A capacitor of capacitance CC and an inductor of inductance LL are connected to a DC battery as shown at t=0t = 0, the switch is closed. Choose correct option(s).

A

Polarity of charge on capacitor never reverses with time.

B

Maximum charge on capacitor is 2CV2CV.

C

Maximum current in the circuit is VCLV\sqrt{\frac{C}{L}}.

D

Maximum current in the circuit is 2VCL2V\sqrt{\frac{C}{L}}.

Answer

A, B, C

Explanation

Solution

The circuit equation is VLdidtqC=0V - L \frac{di}{dt} - \frac{q}{C} = 0. With initial conditions q(0)=0q(0)=0 and i(0)=0i(0)=0, the charge is q(t)=CV(1cos(ωt))q(t) = CV(1 - \cos(\omega t)) and current is i(t)=VCLsin(ωt)i(t) = V\sqrt{\frac{C}{L}} \sin(\omega t), where ω=1LC\omega = \frac{1}{\sqrt{LC}}.

  • A: q(t)0q(t) \ge 0, so polarity never reverses.
  • B: qmax=CV(1(1))=2CVq_{max} = CV(1 - (-1)) = 2CV.
  • C: imax=VCLsin(ωt)max=VCLi_{max} = V\sqrt{\frac{C}{L}} |\sin(\omega t)|_{max} = V\sqrt{\frac{C}{L}}.