Question
Physics Question on electrostatic potential and capacitance
A capacitor of capacitance 50pF is charged by 100V source. It is then connected to another uncharged identical capacitor. Electrostatic energy loss in the process is _____ nJ.
Answer
Loss in electrostatic energy
=21(21CV2)
=21×21×50×10−12×(100)2
=4500 nJ
=125 nJ
So, the answer is 125 nJ.