Question

A capacitor of capacitance $5 \mu F$ is connected as shown in the figure. The internal resistance of the cell is 0.5Ω. The amount of charge on the capacitor plate is

• A. $0 \mu C$
• B. $5 \mu C$
• C. $10 \mu C$
• D. $25 \mu C$

Answer 1

Answer: (C)

$10 \mu C$

Answer 2

In steady state current drawn from the battery

In steady state capacitor is fully charged hence No current will flow through line (2)

Hence potential difference across line (1) is

, the same potential difference appears across the capacitor, so charge on capacitor

$Q = 5 \times 2 = 10 \mu C$