Question
Physics Question on Electromagnetic induction
A capacitor of 5μF is charged to a potential difference of 200V. If it is discharged through two resistors of 700 and 300 ohms, what is the energy dissipated in each of the two resistors ?
A
0.07 J, 0.03 J
B
0.03 J,0.07 J
C
0.7 J, 0.3 J
D
0.3 J,0.7 J
Answer
0.07 J, 0.03 J
Explanation
Solution
Current in the circuit is given by : l2 [700+300] = 21×5×10−6×(200)2 This gives ; l2=0.1×10−3 Hence H1=l2R1 = 0.07 J And H2=I2R2 = 0.03 J