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Question

Physics Question on Electromagnetic induction

A capacitor of 5μF5\,\mu\,F is charged to a potential difference of 200V. If it is discharged through two resistors of 700 and 300 ohms, what is the energy dissipated in each of the two resistors ?

A

0.07 J, 0.03 J

B

0.03 J,0.07 J

C

0.7 J, 0.3 J

D

0.3 J,0.7 J

Answer

0.07 J, 0.03 J

Explanation

Solution

Current in the circuit is given by : l2l^2 [700+300] = 12×5×106×(200)2\frac{1}{2} \times 5 \times 10^{-6} \times (200)^2 This gives ; l2=0.1×103l^2 = 0.1 \times 10^{-3} Hence H1=l2R1H_1 = l^2\, R_1 = 0.07 J And H2=I2R2H_2 = I^2R_2 = 0.03 J