Solveeit Logo

Question

Question: A capacitor of \(20 \mu F\) is charged upto 500V is connected in parallel with another capacitor o...

A capacitor of 20μF20 \mu F is charged upto 500V is connected in parallel with another capacitor of 10μF10 \mu F which is charged upto 200V. The common potential is

A

500V

B

400V

C

300V

D

200V

Answer

400V

Explanation

Solution

By using V=C1V1+C2V2C1V2V = \frac { C _ { 1 } V _ { 1 } + C _ { 2 } V _ { 2 } } { C _ { 1 } V _ { 2 } }; C1 = 20 μF, V1 = 500 V, C2 = 10 μF and V2 = 200 V

V=20×500+10×20020+10=400 VV = \frac { 20 \times 500 + 10 \times 200 } { 20 + 10 } = 400 \mathrm {~V}