Question

A capacitor of 10 mF is connected to a source of
50 V and then disconnected. When the space between the plates is filled with teflon of dielectric constant 2.5. The new potential difference is–

• A. 20 V
• B. 20.8 V
• C. 23.8 V
• D. 25 V

Answer 1

Answer: (A)

20 V

Answer 2

Battery disconnected so Q = constant

C' = 2.5 C

V =

\ V' = = $\frac { 50 } { 2.5 }$ = 20 volt