Question

A cannon ball is fired from a building of height h at the sea shore with a velocity v at an angle of a upwards from the horizontal, targeting a ship at a horizontal distance of S from the shore, as shown in the figure. If 'g' denotes the acceleration due to gravity, tan $\alpha$ governed by the quadratic equation is

• A. $\frac{g}{2v^{2}} \tan^{2} \alpha+\frac{h}{s} \tan\alpha + \frac{gs }{2v^{2}}=0$
• B. $\frac{g}{2v^{2}} \tan^{2} \alpha - \frac{h}{s} \tan\alpha + \frac{gs }{2v^{2}}=0$
• C. $\frac{g}{2v^{2}} \tan^{2} \alpha + \tan\alpha + \frac{gs }{2v^{2}} - \frac{h}{s}=0$
• D. $\frac{g}{2v^{2}} \tan^{2} \alpha - \tan\alpha + \frac{gs }{2v^{2}} - \frac{h}{s}=0$

Answer 1

Answer: (D)

$\frac{g}{2v^{2}} \tan^{2} \alpha - \tan\alpha + \frac{gs }{2v^{2}} - \frac{h}{s}=0$

Answer 2

Answer (d) $\frac{g}{2v^{2}} \tan^{2} \alpha - \tan\alpha + \frac{gs }{2v^{2}} - \frac{h}{s}=0$