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Question: A caloriemeter contains 0.2*kg* of water at 30<sup>0</sup>*C*. 0.1 *kg* of water at 60<sup>0</sup>*C...

A caloriemeter contains 0.2kg of water at 300C. 0.1 kg of water at 600C is added to it, the mixture is well stirred and the resulting temperature is found to be 350C. The thermal capacity of the caloriemeter is

A

6300 J/K

B

1260 J/K

C

4200 J/K

D

None of these

Answer

1260 J/K

Explanation

Solution

Let X be the thermal capacity of calorimeter and specific heat of water = 4200 J/kg-K

Heat lost by 0.1 kg of water = Heat gained by water in calorimeter + Heat gained by calorimeter

0.1×4200×(6035)=0.2×4200×(3530)+X(3530)0.1 \times 4200 \times (60 - 35) = 0.2 \times 4200 \times (35 - 30) + X(35 - 30) 10500 = 4200 + 5X ⇒ X = 1260 J/K