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Question: A: Calculate the difference between the simple interest and the compound interest on \({\rm{Rs}}{\rm...

A: Calculate the difference between the simple interest and the compound interest on Rs.  4000{\rm{Rs}}{\rm{.}}\;{\rm{4000}} in 2{\rm{2}} years at 8%{\rm{8\% }} per annum compounded yearly.
B: On a certain sum of money, the difference between the compound interest for a year, payable half yearly and the simple interest for a year is Rs.  180/{\rm{Rs}}{\rm{.}}\;180{\rm{/ - }}. Find the sum lent out, if the rate of interest in both the cases is 10%{\rm{10\% }} per annum. Then, find 10A+B{\rm{10}}A + B.
A) 7225672256
B) 720256720256
C) 722056722056
D) 722506722506

Explanation

Solution

Formula for simple interest is,
SI=P×n×r100SI = \dfrac{{P \times n \times r}}{{100}}.
Formula for compound interest is,
CI=P(1+r100)nPCI = P{\left( {1 + \dfrac{r}{{100}}} \right)^n} - P.
Formula for compound interest for half yearly is,
CI=P[1+(R2)100]2nPCI = P{\left[ {1 + \dfrac{{\left( {\dfrac{R}{2}} \right)}}{{100}}} \right]^{2n}} - P

Complete step by step answer:
In case A,
Given, principle amount, P=4000P = 4000
Time, n=2  yearsn = 2\;{\rm{years}}
Rate of interest, r=8%r = 8\%
Step I:
Now, formula for simple interest is,
SI=P×n×r100SI = \dfrac{{P \times n \times r}}{{100}}
Now, place the values of P, n,and r in the above equation we get,
SI=P×n×r100 =4000×2×8100 =640  Rs.\begin{array}{c}SI = \dfrac{{P \times n \times r}}{{100}}\\\ = \dfrac{{4000 \times 2 \times 8}}{{100}}\\\ = 640\;{\rm{Rs}}{\rm{.}}\end{array}

Therefore, simple interest is 640  Rs.640\;{\rm{Rs}}{\rm{.}}
Step II
Again, formula for compound interest is,
CI=P(1+r100)nPCI = P{\left( {1 + \dfrac{r}{{100}}} \right)^n} - P
Now, place the values of P, n,and r in the above equation we get, CI=P(1+r100)nP =4000×(1+8100)24000 =(4000×2725×2725)4000 =46654000 =665\begin{array}{c}CI = P{\left( {1 + \dfrac{r}{{100}}} \right)^n} - P\\\ = 4000 \times {\left( {1 + \dfrac{8}{{100}}} \right)^2} - 4000\\\ = \left( {4000 \times \dfrac{{27}}{{25}} \times \dfrac{{27}}{{25}}} \right) - 4000\\\ = 4665 - 4000\\\ = 665\end{array}
Therefore, the compound interest is 665.6665.6 Rs.
Now, difference between the simple interest and the compound interest
=665.6640 =25.6  Rs.\begin{array}{c} = {\rm{665}}{\rm{.6}} - {\rm{640}}\\\ = {\rm{25}}{\rm{.6}}\;{\rm{Rs}}{\rm{.}}\end{array}
Hence, A=25.6A = 25.6
Part B:
Given, rate of interest, r=10%r = 10\%
Difference between compound interest and simple interest,
CISI=180CI - SI = 180
For simple interest,
n=1n = 1, r=10%r = 10\%
Therefore, simple interest,
SI=Pnr100 =P×1×10100 =P10\begin{array}{c}SI = \dfrac{{Pnr}}{{100}}\\\ = \dfrac{{P \times 1 \times 10}}{{100}}\\\ = \dfrac{P}{{10}}\end{array}
Formula for half-yearly compound interest,
CI=P[1+(R2)100]2nPCI = P{\left[ {1 + \dfrac{{\left( {\dfrac{R}{2}} \right)}}{{100}}} \right]^{2n}} - P
For compound interest,
n=1n = 1, r=10%r = 10\%
Therefore, compound interest,
CI=P[1+(R2)100]2nP =P[1+(102)100]2P =P[1+5100]2P =P[105100]2P =P[2120]2P =441P400P =41P400\begin{array}{c}CI = P{\left[ {1 + \dfrac{{\left( {\dfrac{R}{2}} \right)}}{{100}}} \right]^{2n}} - P\\\ = P{\left[ {1 + \dfrac{{\left( {\dfrac{{10}}{2}} \right)}}{{100}}} \right]^2} - P\\\ = P{\left[ {1 + \dfrac{5}{{100}}} \right]^2} - P\\\ = P{\left[ {\dfrac{{105}}{{100}}} \right]^2} - P\\\ = P{\left[ {\dfrac{{21}}{{20}}} \right]^2} - P\\\ = \dfrac{{441P}}{{400}} - P\\\ = \dfrac{{41P}}{{400}}\end{array}
Difference between compound interest and simple interest,
CISI=18041P400P10=18041P40P400=180P400=180=72000\begin{array}{c}CI - SI = 180\\\\\dfrac{{41P}}{{400}} - \dfrac{P}{{10}} = 180\\\\\dfrac{{41P - 40P}}{{400}} = 180\\\\\dfrac{P}{{400}} = 180\\\P = 72000\end{array}
Hence, the principal amount is 7200072000 Rs.
Hence, B=72000B = 72000
Now, calculate the value of 10A+B{\rm{10}}A + B
Place the value of A=25.6A = 25.6 and B=72000B = 72000 in the above equation.
10A+B=(10×25.6)+72000 =256+72000 =72256\begin{array}{c}{\rm{10}}A + B = \left( {10 \times 25.6} \right) + 72000\\\ = 256 + 72000\\\ = 72256\end{array}

Note: Simple Interest: Simple interest is a convenient and fast way to measure the interest rate on a loan. Simple interest is measured by the calculation by the principal of the nominal interest rate by the amount of days between payments that pass. Formula for simple interest is, SI=P×n×r100SI = \dfrac{{P \times n \times r}}{{100}}.
Compound interest: Compound interest is applying debt to the principal balance of a loan or savings, or return on equity, in other words. That is the product of reinvesting interest, rather than taking it off, such the interest on the principal balance and previously accrued interest is then paid in the next cycle. Formula for compound interest is,
CI=P(1+r100)nPCI = P{\left( {1 + \dfrac{r}{{100}}} \right)^n} - P.
Formula for compound interest for half yearly is,
CI=P[1+(R2)100]2nPCI = P{\left[ {1 + \dfrac{{\left( {\dfrac{R}{2}} \right)}}{{100}}} \right]^{2n}} - P

Hence the correct answer is option A.